how many integers are there between -100 and 100 divisible by 3.. arithemetic progression
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how many integers are there between -100 and 100 divisible by 3.. arithemetic progression
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Answer:
From the question, it is given that,
First term a=17
Common difference =14−17=−3
Last term l=−40
L=a+(n−1)d
−40=17+(n−1)(−3)
−40−17=−3n+3
−57−3=−3n
n=−60/−3
n=20
Therefore, 6th term form the end
=l−(n−1)d
=−40−(6−1)(−3)
=−40−(5)(−3)
=−40+15
=-25