how many oxygen atoms are present in 88g of carbon dioxide
with explanation
Share
how many oxygen atoms are present in 88g of carbon dioxide
with explanation
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
number of atom=1.2044×10^24
Explanation:
number of mole=88÷44=2mol
number of atom =2mol×6.022×10^23=12.044×10^23=1.2044×10^24
Answer:
hey mate here is your answer:
Explanation:
As one molecule of CO contains 1 atom of oxygen, therefore there are 6.023 X 1023 atoms of oxygen present in 6.023 X 1023 molecules of CO.
molar mass of CO2= 12 + 16 x 2 = 44g
44g of CO2 gives 1 mol of CO2
88g of CO2 gives 2 mol of CO2
1 mol of CO2 has 2 mol of O2
2 mol of Co2 has 4 mol of O2
So,
number of atoms = no. of moles x Avogadro's number = 4 x 6.023 x 10²³
hope it will help you...