How many zeroes will be at the end of 130! ?
Explain the answer without using actual multiplication.
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How many zeroes will be at the end of 130! ?
Explain the answer without using actual multiplication.
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the denominator is divisible by 16+14=30 factors of 5. Therefore, the quotient 130! 70! 60! is divisible by 32−30=2 factors of 5, which suggests that (13070) ends in two zeros.