how to find oxidation number of electrons number of neutrons electronic configuration of the following
1. 11 Na ^23
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how to find oxidation number of electrons number of neutrons electronic configuration of the following
1. 11 Na ^23
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Answer:
Here Substracte atomic number from atomic mass you can get number of neutron and its valency +1 is for 1A group +2 for 2A group +3 for 3A group +4 some time -4 for 4A group -3 for 5A group -2 for 6A group -1 for 7A group 0 For 8 Agroup if your question is that what is oxdition number of Cl? in NaCL THEN I CAN CALCULATE OXIDATION NUMBER. because oxidation number is formal charge in atom of a compound
and electronic configuration with the help of aufbua principle