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Given Equation is px - 3y = 1
On comparing with a1x + b1y + c1 = 0,
a1 = p, b1 = -3, c1 = -1 ----- (1)
Given Equation is -12x + py = 2
a2 = -12, b2 = p, c2 = -2 ----- (2)
Now,
Given System of linear Equations have infinite number of solutions.So,
= > (a1/a2) = (b1/b2) = (c1/c2)
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(i)
= > p = 6,-6.
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(ii)
= > p = -6.
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Here, p = -6 satisfies both equations.
Therefore, The value of p = -6.
Hope this helps!
Verified answer
Px-3y = 1.............. (1)-12x+py = 2.......... (2)
In case of infinitely many solution
a1 = p b1 = - 3 c1 = - 1
a2 = -12 b2 = p c2 = - 2
a1/a2 = b1/b2 = c1/c2
-p/12 = - 3/p = 1/2
p^2 = 36
p = 6
Ans......