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AB || CD and CD || EF
therefore AB || EF
Now , angle EFA = Angle FAB = 80° - 1 equa.
( alternate interior angles )
If AB ||CD , then
angle DCA + angle CAB = 180° (consecutive angles )
140° + angle CAB = 180°
angle CAB = 180°- 140° = 40°
angle FAB = 80° ( from 1 equa.)
angle FAC = angle FAB - Angle CAB
= 80° - 40°= 40°
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