A driver of a car travelling at 52km/hr applies brakes and
accelerates uniformly in the opposite direction the car stops in 5
seconds. Another driver going at 34km/hr in another car applies brakes
slowly and stops in 10 seconds.
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A driver of a car travelling at 52km/hr applies brakes and
accelerates uniformly in the opposite direction the car stops in 5
seconds. Another driver going at 34km/hr in another car applies brakes
slowly and stops in 10 seconds.
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Answer:
Given :
First Car A:
Initial Velocity= u= 52 km/hr=52x5/18=14.4 m/s
Final velocity= V= 0m/s
time =t=5sec
Refer attachment for Graph :
Distance travelled : Area of traingle AOB =1/2 OB x AO
=(1/2)x 14.4 x 5=72/2=36m
Second Car B:
Initial Velocity= u= 3 km/hr=3x5/18=0.83m/s
Final velocity= V= 0m/s
time =t=10sec
Refer attachment for Graph :
Distance travelled : Area of traingle COD =1/2 OD x CO=(1/2)x 0.83 x 10=4.1m
So, after applying of brakes , Car A has travelled a distance of 3m and car B has travelled a distance of 4.1m.
∴ Car B has travelled farther than Car A after the brakes are applied.
Explanation:
Answer:
Conversatio from Km/h to m/s
1 km=1000m
1 hr=60minutes=3600seconds
:.1km=1000m
hr 3600sec
:. 1km/hr=5/18m/s
CAR 1
Initial velocity=52km/h
=52 x 5
18
=130
18
=14.44m/s
Final velocity=0m/s
Time=5 seconds
CAR 2
Initial velocity=5km