a car is moving with a velocity of 72 km/hr . On the application of brakes , car stops in 10 seconds .
Find 1. retardation.....
2. distance covered by the car before it stops .....
3. braking force if mass of car is 800 kg.....
need answer urgent..
plz help
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✪AnSwEr
72km/h
by multiplying by 5/18
NOW
=72 *5/18
u=20m/s
From equation of motion
v=u+at
=>v=20+10a
=>0=20+10a
=>-2=a
From equation of motion
v²=u²+2as
=>0=400-4s
=>-400=-4s
=>s=100
Now force
force = mass × acceleration
=>f=800×-2
=>f=-1600
Verified answer
Answer:
u= 72km/hr=72x5/18=20km/hr
t= 10s
v=0
v=u+at
0=20+10a
-20=10a
a = -2m/s^2
s=ut + 1/2 at^2
s= 20x10+1/2x-2x100
s= 200-100
s=100m
f=ma
f=800x-2
f=-1600 kg m/s
Hope it helps