A bdy moving with speed of 30km/hr towards east turns sharply towards north , the magnitude of change of velocity is
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A bdy moving with speed of 30km/hr towards east turns sharply towards north , the magnitude of change of velocity is
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Answer:
a car Will goes to 40 km/hr
Answer:
30√2 km/hr
Explanation:
Let the east be +x axis and north be +y axis
Intital velocity vi = (30î)km/hr
Final velocity vf = (30j)km/hr
Change in velocity = vf - vi
= 30j - 30î
magnitude |vf - vi| = | (-30i + 30j) |
= √ 30² + 30² + 2(30)²cos90°
= √ 2×30²
= 30√2 km/hr