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Answer:
pQ=pR(given)
ps =pQ(given)
In triangle pQR and triangle RQS
PQ= PR(Given)
PS =PQ(given)
QR=RQ(common)
bySSS Triangle pQR CONGRUENCE RQS..
angle PQR= RQS ( BY CPCT)
BY ANGLE SUM PROPERTY OF TRIANGLE..
angle PQR +angle RQS = 180 DEGREE
angle pQR = angle RQS ( above proved)
So;
angle RQS +angle RQS= 180 DEGREE
2 RQS = 180 DEGREE
RQS = 180/2
.. . RQS = 90 DEGREEE......
Answer is fully correct.
Answer:
by corresponding angles wecan prove that
Step-by-step explanation:
Given : pq=pr
ps=pq
to show :∆QRS is right angle
answer : (pq =pr
ps=pq) given
pq =pr=ps
p is the mid point of QS
let M be the mid point of QR
then,∆QMP is right angle triangle
(pq=pr , QR=MR , PM is common)
QR square + PM square=PQ square
P is the mid point of QS
therefore ∆QMP ~∆QRS
so ∆QMP IS THE RIGHT ANGLE TRIANGLE so ∆QRS will be the RIGHT ANGLE TRIANGLE
In similar ∆QRS IS CORRESPONDING ANGLE IS EQUAL
HENCE PROVED THAT
( ∆QRS IS THE RIGHT ANGLE TRIANGLE)