if 10n of force is applied on a 5 kg mass at rest for 5 seconds then velocity achieved is
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if 10n of force is applied on a 5 kg mass at rest for 5 seconds then velocity achieved is
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Answer:
given, f=10n
m=5kg
t=5sec
u=0
so v=?
using force formula f= ma
10 =5a
a=10/5=2m/s
using first equation of motion =
v=u+at
v=0+2*5
v =10m ans
Explanation:
given
Force 10N
Mass of object 5 kg
time 5 sec
F=ma
by putting values
10 = 5a
a = 2 m/s²
by 1 st equation of motion
V= u +at
object is at rest so u= 0
then
V= at
by putting values
V = 2(5)
so V = 10 m/s