if 1&2 are two zeroes of the polynomial x³-6x²+ax+b, then find the value of a &b
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if 1&2 are two zeroes of the polynomial x³-6x²+ax+b, then find the value of a &b
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Step-by-step explanation:
P(1)=(1^3)-6(1^2)+a1+b=0
=3-12+a+b=0
= -9+a+b=0
=a+b=9----------(1)
P(2)=(2^3)-6(2^2)+2a+b=0
=8-24+2a+b=0
=-16+2a+b=0
=2a+b=16-------(2)
From (1) and(2)
( 2a+b=16)-( a+b=9)
=a=7
putting a=7 in (1)
7+b= 9
b=2