If 2 and 3 are zeros of polynomial 3x^2 - 2kx + 2p, find the value of K and P
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If 2 and 3 are zeros of polynomial 3x^2 - 2kx + 2p, find the value of K and P
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3(2)^2-2k(2)+2p = 3(3)^2-2k(3)+2p
12-4k+2p=27-6k+2p
12-4k =27-6k
6k-4k=27-12
2k=15k
k=7.5
substitute value of k in any one of the equations
12-4k+2p=0
12-4(7.5)+2p=0
12-30+2p=0
-18+2p=0
2p=18
p=9
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if 2 and 3 are zeros of the polynomial then if you put X =3 and X=2 both the equation s should be equal to zero which means p(2)=p(3)
3(2)^2-2k(2)+2p = 3(3)^2-2k(3)+2p
12-4k+2p=27-6k+2p
12-4k =27-6k
6k-4k=27-12
2k=15k
k=7.5
substitute value of k in any one of the equations
12-4k+2p=0
12-4(7.5)+2p=0
12-30+2p=0
-18+2p=0
2p=18
p=9