If 2 sin θ – 2 = 0 and 0° ≤ θ ≤ 90°, find the value of θ.
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Answer and Step by step explanation
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 2
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):2sin(θ)/2 = 2/2
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):2sin(θ)/2 = 2/2sin(θ) = 1
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):2sin(θ)/2 = 2/2sin(θ) = 1Step 3: To find θ, take the inverse sine (arcsin) of 1, since sin(θ) = 1 when θ is 90 degrees:
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):2sin(θ)/2 = 2/2sin(θ) = 1Step 3: To find θ, take the inverse sine (arcsin) of 1, since sin(θ) = 1 when θ is 90 degrees:θ = arcsin(1)
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):2sin(θ)/2 = 2/2sin(θ) = 1Step 3: To find θ, take the inverse sine (arcsin) of 1, since sin(θ) = 1 when θ is 90 degrees:θ = arcsin(1)Step 4: The arcsin(1) is 90 degrees.
The equation is 2sin(θ) - 2 = 0. To solve for θ, follow these steps:Step 1: Add 2 to both sides of the equation:2sin(θ) - 2 + 2 = 0 + 22sin(θ) = 2Step 2: Divide both sides by 2 to isolate sin(θ):2sin(θ)/2 = 2/2sin(θ) = 1Step 3: To find θ, take the inverse sine (arcsin) of 1, since sin(θ) = 1 when θ is 90 degrees:θ = arcsin(1)Step 4: The arcsin(1) is 90 degrees.So, θ = 90 degrees.