If –4 is a zero of the polynomial
x²–x–(2+2k), then find the value of k.
The best and correct answer would surely marked as brainliest, while unwanted would be reported immediately.
Share
If –4 is a zero of the polynomial
x²–x–(2+2k), then find the value of k.
The best and correct answer would surely marked as brainliest, while unwanted would be reported immediately.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
hey mate,, here is your answer..
Step-by-step explanation:
f(x) = x²–x–(2+2k)
:– x = -4
:– f(-4) = (-4)^2 - (-4) - 2 - 2k
0 = 16 + 8 - 2 -2k
0 = 24 - 2 - 2k
0 = 22 - 2k
2k = 22
k = 22/2
:– k = 11
hope it helps u frnd !
Answer:
k = 9
Step-by-step explanation:
p(x) = x² - x - (2+2k)
Putting x = -4,
p(-4) = (-4)² - (-4) - 2 - 2k
0 = 16 + 4 - 2 - 2k
0 = 18 - 2k
2k = 18
k = 18/2
k = 9
Hope it helps!