if 4sino-3coso=0 find sino,seco
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Answer :
Solution :
We have ,
=> 4sinϴ - 3cosϴ = 0
=> 4sinϴ = 3cosϴ
=> sinϴ/cosϴ = 3/4
=> tanϴ = 3/4
Also ,
We know that , tanϴ = p/b
Thus ,
tanϴ = p/b = 3/4
Here ,
p = 3 and b = 4
Now ,
As per Pythagoras theorem ,
=> h² = p² + b²
=> h² = 3² + 4²
=> h² = 9 + 16
=> h² = 25
=> h = √25
=> h = 5
Now ,
=> sinϴ = p/h
=> sinϴ = 3/5
Also ,
=> secϴ = h/b
=> secϴ = 5/4
Hence ,
sinϴ = 3/5 and secϴ = 5/4