If 5.85 gms of NaCl are dissolved in 90 gms of water, the
mole fraction of NaCl is
(a) 0.1 (b) 0 2 (03 (d) 0.01 0.0196
The molarity of 0.006 mole of NaCl in 100ml solution is
(a) 0.6670.06 (c) 0.006 (d) 0.066 (e) None of these
9.89 of H2SO4 is present in 2 litres of a solution. The
molarity of the solution is
(a) 0.1M X 0.05M (c) 0.2M Ad) 0.01M
What will be the molarity of a solution containing 5g of
sodium hydroxide in 250ml solution
a) 0.5 (6) 1.0 (c) 2.0 (d) 0.1
The normality of 0.3M phosphorus acid (H3PO3) is
(a) 0.1 (6) 0.9 (c) 0.3 let 0.6
Which of the following has maximum number of molecules
16 am of O.
(b) 16 gm of NO
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Verified answer
moles of Nacl=5.85/58.5=0.1
moles of water=90/18=5.0
mole fraction=moles of solvent/(moles of solvent+moles of solute)=0.1/(0.1+5.0)
=0.01