if 7 men and 5 boys can reap 168 hectares in 18 days how many days will 15men and 5boys take to reap 700 hectares one man being able to do 3 times as much as work of a boy............... no spamming pls spammers shall be reported
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if 7 men and 5 boys can reap 168 hectares in 18 days how many days will 15men and 5boys take to reap 700 hectares one man being able to do 3 times as much as work of a boy............... no spamming pls spammers shall be reported
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Given :-
To find :-
Solution :-
Either we convert both data in men or in boys .
Lets convert In boys .
→ 1M = 3B (Efficiency)
→ 7M = 21B
→ 15M = 45B
So, Now, Question becomes ,
if (21B + 5B) = 26B can reap 168 hectares in 18 days , in how many days , (15M + 5B) = 50B will reap 700 hectares.
we know that,
→ B1 * D1 * W2 = B2 * D2 * W1 ( work is indirectly proportional) .
we have now :-
(Reaping is work done here.)
So,
Putting all values now, we get :-
→ 26 * 18 * 700 = 50 * D2 * 168
→ 26 * 18 * 14 = D2 * 168
→ 26 * 18 = D2 * 12
→ 26 * 3 = D2 * 2
→ D2 = 13 * 3
→ D2 = 39 Days. (Ans.)