if a = 2, b= -2, c = 1
a ^ 2 - b ^ 2 - c ^ 2 - 2ab - 2bc - 2ac
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if a = 2, b= -2, c = 1
a ^ 2 - b ^ 2 - c ^ 2 - 2ab - 2bc - 2ac
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Answer:
Let's substitute the given values (a = 2), (b = -2), and (c = 1) into the expression (a² - b² - c² - 2ab - 2bc - 2ac):
[tex]\[ (2)^2 - (-2)^2 - (1)^2 - 2(2)(-2) - 2(-2)(1) - 2(2)(1) \][/tex]
Simplify each term:
[tex]\[ 4 - 4 - 1 + 8 + 4 - 4 \][/tex]
Combine like terms:
[tex]\[ 7 \][/tex]
So, when (a = 2), (b = -2), and (c = 1), the expression (a² - b² - c² - 2ab - 2bc - 2ac) evaluates to 7 ..
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