IF A(-4,8) B(-3,-4) C(0,5) AND D(5,6) ARE THE VERTICES OF A QUADRILATERAL ABCD,find its area .
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IF A(-4,8) B(-3,-4) C(0,5) AND D(5,6) ARE THE VERTICES OF A QUADRILATERAL ABCD,find its area .
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By draw a diagonal and thus two triangles in the quadrilateral ABCD. Then calculate the areas of the two triangles ABC and ADC separately by the formula : 1/2[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)] . Then finally add the two areas which gives you the area of the quadrilateral ABCD.
Answer:
The area of ABCD is 32 units².
Step-by-step explanation:
The vertices of quadrilateral ABCD are A(-4,8) B(-3,-4) C(0,5) and D(5,6).
The area of ABCD is the sum of area of ABC and CDA.
The area of a triangle is
Therefore the area of ABCD is 32 units².