If A, B, C, D are angles of a cyclic quadrilateral, prove
that
cos A + cos B + cos C + cos D=0.
Pls do step by step Pls do Fast
Share
If A, B, C, D are angles of a cyclic quadrilateral, prove
that
cos A + cos B + cos C + cos D=0.
Pls do step by step Pls do Fast
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
mark me as brainlest. ...
so I can go to next level
pls bro
If A,B,C and D are angles of a cyclic quadrilateral prove that
cosA+cosB+cosC+cosD=0
ANSWER
Since the quadrilateral ABCD is cyclic, we have
A+C=180
o
;B+D=180
o
Hence, cosA=cos(180
o
−C)=−cosC...(1) and cosB=cos(180
o
−C)=−cosD...(2)
Adding (1) and (2) we get
cosA+cosB=−cosC−cosD
or cosA+cosB+cosC+cosD=0
Answer:
Suniye na plz inbox kijiye na