if a-b,a and a+b are zeroes of the polynomial x^3-3x^2+x+1,the value of (a+b) is
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if a-b,a and a+b are zeroes of the polynomial x^3-3x^2+x+1,the value of (a+b) is
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Let α=a-b
β=a
γ=a+b
α+β+γ=-x² coefficient/x³ coefficient
a-b+a+a+b=-3/1
3a=-3
a=-3/3
a= -1
αβγ= -constant/x³ coefficient
(a-b)(a)(a+b)=-1/1
(a²-b²)(a)= -1
[(-1)²-b²](-1)=-1
(1-b²)= -1/-1
1-b²=1
1-1=b²
b²=0
b=√0=0
Therefore, a=-1 and b=0
Hope it helps