If a conductor is folded 8 times then the resistance will be
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If a conductor is folded 8 times then the resistance will be
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Answer:
Let L be the length and A be the cross sectional area
R=ρ
A
l
=8Ω
l
′
=l/2
A
′
=A/2
R
′
=ρ
A
′
l
′
=ρ
2A
l/2
=
4
1
ρ
A
l
=
4
1
×8=2Ω
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