if a cone height is decreased by 20% and radius is incresed by 20% then what is the percent volume change??? pls answer.........
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if a cone height is decreased by 20% and radius is incresed by 20% then what is the percent volume change??? pls answer.........
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Answer:
according to me the volume will be decreased by 20%
Answer:
let the hight as h and the radius r then the volume will be
[tex] \frac{1}{3} \pi {r}^{2} h \\ [/tex]
if the hight decreased by 20% so the hight will be 4/5h
and the radius 6/5r
[tex] \frac{1}{3} \pi { \frac{6r}{5} }^{2} \frac{4}{5} h \\[/tex]
this would be the new volume