if a pair of dice is tossed simultaneously and the numbers on the upper face are added then what will be the probability of not getting a sum 4 or 8
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if a pair of dice is tossed simultaneously and the numbers on the upper face are added then what will be the probability of not getting a sum 4 or 8
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Answer:
the probability is 7/9
Step-by-step explanation:
there are 36 outcomes out of these only these does not sum to 4 or 8:
(1,3)(2,2)(2,6)(3,1)(3,5)(4,4)(5,3)(6,2)
hence 36-8=28outcomes
p(not getting sum 4 or 8)=28/36
=7/9