If a rectangle has length (4x + 5) and width (2x-3) whose circumference is 40 cm, what is its area?
answer?
class 5th
subject mathematics
Share
If a rectangle has length (4x + 5) and width (2x-3) whose circumference is 40 cm, what is its area?
answer?
class 5th
subject mathematics
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
-120
Step-by-step explanation:
(4*+5)*(2*-3)
20*(-6)
-120
Answer:
If a rectangle has the length (4x + 5) and width (2x-3) whose circumference is 40 cm, its area is [tex]51cm^{2}[/tex]
Step-by-step explanation:
The circumference of a rectangle is the total linear distance along its boundary
if the length of the rectangle is represented as [tex]l[/tex] and breadth [tex]b[/tex] as shown in the figure then the circumference is equal to [tex]2l+2b[/tex]
From the question, it is given that
the length of the rectangle is [tex]l=(4x+5)[/tex]
and the breadth is [tex]b=(2x-3)[/tex]
therefore the circumference is [tex]=2(4x+5)+2(2x-3)=12x+4[/tex]
but circumference is [tex]40cm[/tex]
⇒
[tex]12x+4=40\\12x=36\\x=36/12=3cm[/tex]
substitute the value of x in length and breadth, we get
[tex]l=(4*3+5)=17cm\\b=(2*3-3)=3cm[/tex]
the area of a rectangle is [tex]A=l*b[/tex]
[tex]A=17*3=51cm^{2}[/tex]