If a triangle’s base is two times the length of its altitude, what is the area of a triangle whose altitude is 8 m?
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If a triangle’s base is two times the length of its altitude, what is the area of a triangle whose altitude is 8 m?
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Answer:
64
Step-by-step explanation:
area of triangle=½*b*h
½*8*16=64cm²
Answer:
Step-by-step explanation:
AREA OF TRIANGLE = 1/2* b* h
given that,
b = 2h
b = 2(8)
b = 16
Area = 1/2* b*h
= 1/2*16*8
= 8*8
Area = 64