if Alfa ,beta ,GA are zeroes of x^+3x^-x-3then find 1÷alfa+1+beta+1÷gama
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if Alfa ,beta ,GA are zeroes of x^+3x^-x-3then find 1÷alfa+1+beta+1÷gama
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Answer:
=-1/3
Step-by-step explanation:
we have equation,
x³+3x²-x-3.
we know formula for zeros,
[tex]\alpha +\beta +\gamma = \frac{-b}{a}[/tex]
[tex]\alpha\times \beta \times \gamma=\frac{-d}{a}[/tex]
[tex]\alpha\beta +\beta\gamma +\gamma \alpha=\frac{c}{a}[/tex]
A/Q,
=>1/alpha + 1/beta+ 1/ gamma = alpha beta +beta gamma + gamma alpha /alpha beta gamma
=>-1/3.
Answer: