if an object is thrown vertically upward with a speed 49 MS -1 how long does it take to complete upward in journey what maximum height does it achieve
if an object is thrown vertically upward with a speed 49 MS -1 how long does it take to complete upward in journey what maximum height does it achieve
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0=49-9.8t
t=5
(ii)v^2=u^2 +2as
0= 49*49-2*9.8s
s=49*49/19.6
s=245/2
s=122.5