if anybody will answer this I will make you brainlist
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To find the maximum range, you need time of flight
when gun is fired horizontal to surface
the y-component of velocity will be zero
so
let the gun be fired at 'H' height from ground
then
T(time of flight)= sq.root(2H/g)
then let muzzle velocity be V
given horizontal range = X
then
V × T = X
V = X/T
substitute and reach the answer
Sure. The maximum range of a gun along horizontal can be found using the following formula:
R = (u^2 * sin(2 * theta)) / g
where:
Plugging in the given values:
Solving for u:
Therefore, the muzzle velocity of the shell is 400 m/s. The answer is 1) 400.
Hope it helps...✨