if for an a.p first term us 2 and common difference is 3 find sn and s12
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if for an a.p first term us 2 and common difference is 3 find sn and s12
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a=2 and d= 3
Sn= n/2{2a+n-1)d = n/2 {4+(n-1)3}
Sn = n/2 (3n+1) = 3n²+n / 2
and
S12 = 12/2 {2×2+(12-1)3} = 6 {4+11×3}= 6×37 = 222
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