If I have to predict again a square made by select any 4 numbers, how will you approach to solve if the sum of all the numbers is given to you?
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If I have to predict again a square made by select any 4 numbers, how will you approach to solve if the sum of all the numbers is given to you?
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Given : a square made by select any 4 numbers on a calendar
To Find : approach to solve find the numbers if the sum of all the numbers is given to you
Solution:
in a calendar in any square 4 numbers are
a a + 1
a+ 7 a + 8
Sum of Square = a + a + 1 + a + 7 + a + 8
= 4a + 16
= 4(a + 4)
If Sum of Square is given Then Divide the sum by 4 and subtract 4
to get top left number
S/4 - 4 = b
then rest numbers are
b b +1
b + 7 b + 8
for example sum = 20
=>20/4 - 4 = 1
1 2
8 9
Sum = 24
=> S/4 - 4 = 2
2 3
9 10
General rule :
S/4 - 4 S/4 - 3
S/4 + 3 S/4 + 4
S is sum of all four numbers
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