If l, m and n are the direction cosines of a vector, then
A) l+m+n=1
B) l^2+m^2+n^2=1
C) l^2+m^2+n^2=0
D) l+m+n=0
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If l, m and n are the direction cosines of a vector, then
A) l+m+n=1
B) l^2+m^2+n^2=1
C) l^2+m^2+n^2=0
D) l+m+n=0
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Answer:
B). l²+m²+n² = 1
Explanation:
l = cos(a) = x/r
m = cos(b) = y/r
n = cos(c) = z/r
where r = √x²+y²+z²
where a,b,c are the angles made by the direction vector with x,y,z axes
So, l²+m²+n² = 1 Ans.
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Answer:
ya (option b) is the answer