if m and n are zeroes of polynomial x² +(a+1)x +b then find value of a and b
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if m and n are zeroes of polynomial x² +(a+1)x +b then find value of a and b
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Answer:
[tex] {m}^{2} + (a + 1)m + b = 0 \\ \\ {n}^{2} + (a + 1)n + b = 0 \\ \\ {m}^{2} - {n}^{2} + ma - na + m - n = 0 \\ \\ (m + n) + a + 1 = 0 \\ \\ a = - m - n - 1. \\ \\ solving \: \: \: \: we \: get \\ \\ {m}^{2} +( - m - n)m + b = 0 \\ b = mn.[/tex]
Step-by-step explanation:
[tex]a = - m - n - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: b = mn[/tex]