If one side of a square is increased by 5metres and the other side is reduced by 5 metres , a rectangle is formed whose perimeter is 30 m . Find the side of the original square .
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If one side of a square is increased by 5metres and the other side is reduced by 5 metres , a rectangle is formed whose perimeter is 30 m . Find the side of the original square .
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✴ Required Answer:
✏GiveN:
✏To FinD:
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✴ How to solve?
Here, we need to maximise and minimise the sides of the square to form a rectangle. We need to know,
By keeping these points in mind, let's solve the question.
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✴ Solution:
Let the side of the square be x
It was changed to a rectangle with l and b,
Given,
By using formula for perimeter of rectangle,
✏ We had our side of square = x,
So, x = 7.5 m
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Verified answer
In a square, all the sides are equal.
Let the side of the square be x.
Therefore, the sides of the rectangle are (x+5) and (x - 5) .
The perimeter of the rectangle is
2[(l+b)
=2[( x+5) + (x - 5)]
=2x + 10 + 2x - 10
= 4x
Now,
4x = 30
= x = 30/4
= x = 7.5