if percentage error of measurement in velocity and Mass 2 % and 4 % respectively what is the percentage error in kinetic energy
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if percentage error of measurement in velocity and Mass 2 % and 4 % respectively what is the percentage error in kinetic energy
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=>∆k/k ×100 = ∆m/m ×100 + 2∆v/v ×100
=> ∆k/k ×100= 4+2(2) =4+4=8
hence, the % error in measurement of kinetic energy is 8%
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