if side of isosceles is 14 cm then what is it's area?
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if side of isosceles is 14 cm then what is it's area?
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Answer:
Step-by-step explanation:
Let sides are 5x, 5x and 4x.
Therefore, 5x+5x+4x = 14
14x= 14
x=1
Therefore sides are 5cm, 5cm and 4cm.
S= a+b+c/2 = 5+5+4/2 = 7
Area= √ s(s-a)(s-b)(s-c)
=√ 7(7-5)(7-5)(7-4)
=√ 7x 2x 2x 3
2√21
hope it helps u..
Answer:
If it is a right isosceles triangle area is 98 cm^2
Step-by-step explanation:
Area of the triangle is
ATQ
-------
side is 14 base and height is 14
1/2 × b× h u^2
= 1/2 × 14×14 cm^2
= 7×14 cm^2
= 98 cm^2
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