if tan A is equals to 12 by 5 then show that tanA into Cos A minus sinA is equals to 35 by 136.can anyone tell me fast.....
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if tan A is equals to 12 by 5 then show that tanA into Cos A minus sinA is equals to 35 by 136.can anyone tell me fast.....
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Answer:
Cos A = 12/13
sin ^2 A = 1 - cos ^2 A
= 1- (12/13)^2
= 1 - 144/169
= (169 -144)/169
=25/169
therefore
sin A = 5/13
tan A = sin A / cos A = (12/13)/(5/13) = 12/5
lhs = sin A(1-tan A) = 12/13 *( 1 - 12/5)
= 12/13 * (-5-12)/5
=12/13 * (-17)/5
=- (12*17)/65
this is not equal to rhs
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