If tangents PA and PB from a point P to a circle with center O are inclined to each other at angle of 80° , then angle POA is equal to:-
a. 50°
b. 60°
c. 70°
d. 80°
plz answer this question fast
don't post any irravelent answer....
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If tangents PA and PB from a point P to a circle with center O are inclined to each other at angle of 80° , then angle POA is equal to:-
a. 50°
b. 60°
c. 70°
d. 80°
plz answer this question fast
don't post any irravelent answer....
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Answer:
A = 50°
Step-by-step explanation:
If you have figure of question then:
In triangle POA:
angleOAP = 90° ( THEOREM )
angle APO=40° ( CONSIDER LINE OP AS BISECTOR 80/2 )
SO angle POA= 180-130
= 50°
Verified answer
Answer:
A = 50°
Step-by-step explanation:
If you have figure of question then:
In triangle POA:
angleOAP = 90° ( THEOREM )
angle APO=40° ( CONSIDER LINE OP AS BISECTOR 80/2 )
SO angle POA= 180-130
= 50°
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