If tanθ+sinθ=m and tanθ-sinθ=n then (m²-n²)²=?
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Answer:
hey here is your solution
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Step-by-step explanation:
so here
tanθ+sinθ=m
and tanθ-sinθ=n
so to find value of (m²-n²)²
substituting values of m and n in it
we get
[(tanθ+sinθ)²-(tanθ-sinθ)²]²
=[(tan²θ+sin²θ+2tan.sinθ)-(tan²θ+sin²-2tan.sinθ)]²
=[(tan²θ+sin²θ+2tan.sinθ-tan²θ-sin²θ+2tan.sinθ)]²
=(2tan.sinθ+2tan.sinθ)²
=(4tan.sinθ)²
=16.sinθ.tanθ