if the area of rectangle is 56(x²yz+xy²z-xyz²) and it's length is 8xyz then it's breath is?
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if the area of rectangle is 56(x²yz+xy²z-xyz²) and it's length is 8xyz then it's breath is?
if the area of rectangle is 56(x²yz+xy²z-xyz²) and it's length is 8xyz then it's breath is?
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Given :-
To Find :-
Solution :-
Let the breadth be a.
And, We can write,
➙ Area = 56(x²yz + xy²z - xyz²)
➙ Area = 56(xyz(x) + xyz(y) - xyz(z))
➙ Area = 56xyz(x + y - z).
Now, We know that,
Area of Rectangle = Length × Breadth.
Now, Substitute the Values.
➙ 56(x²yz+xy²z-xyz²) = 8xyz × a.
➙ 56xyz(x + y - z) = 8xyz × a.
➙ a = 56xyz(x + y - z)/8xyz
➙ a = 7(x + y - z).
Therefore, Breadth of Rectangle = 7(x + y - z).