if the area of rhombus is 24 cm square and one of its diagonals is 8 cm find the perimeter of the Rhombus
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if the area of rhombus is 24 cm square and one of its diagonals is 8 cm find the perimeter of the Rhombus
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Step-by-step explanation:
A=pq
2
P=4a
a=p2+q2
2
Solving forP
P=2p2+4(A
p)2=2·82+4·(24
8)2=20cm
Answer:
Area of rhombus = 1/2 × d1 × d2.
24 = 1/2 × 8 × d2.
48 = 8 × d2.
d2 = 6cm.
Perimeter of rhombus = 20cm.