* If the base of a cone of 21 cm diameter and 12 cm oblique height is semicircular, then the total surface area is __________. *
1️⃣ 1098 sq. Cm
2️⃣ 1089 sq. Cm
3️⃣ 1079 sq. Cm
4️⃣ 1099 sq cm
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* If the base of a cone of 21 cm diameter and 12 cm oblique height is semicircular, then the total surface area is __________. *
1️⃣ 1098 sq. Cm
2️⃣ 1089 sq. Cm
3️⃣ 1079 sq. Cm
4️⃣ 1099 sq cm
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Given : base of a cone of 21 cm diameter and 12 cm oblique height is hemispherical
To Find : total surface area
1️⃣ 1098 sq. Cm
2️⃣ 1089 sq. Cm
3️⃣ 1079 sq. Cm
4️⃣ 1099 sq cm
Solution:
total surface area = CSA of Cone + CSA of Hemisphere
CSA of Cone = πRL
R = 21/2 cm
L = 12
π = 22/7
CSA of Cone = (22/7)(21/2)12
= 396 cm²
CSA of Hemisphere = 2πR²
= 2(22/7)(21/2)²
= 693 cm²
total surface area is 396 + 693
Correct Option is
= 1089 cm²
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