If the diagonals of a rhombus are 12cm and 16cm, find the length of each side.
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If the diagonals of a rhombus are 12cm and 16cm, find the length of each side.
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Answer:
AC= 16 cm. BD = 12 cm
∴
A
O
=
O
C
=
16
2
=
8
c
m
B
O
=
O
D
=
12
2
=
6
c
m
B
O
=
O
D
=
12
2
=
6
c
m
Now, in right angled
Δ
A
O
B
,
A
B
2
=
A
O
2
+
B
O
2
=
(
8
)
2
+
(
6
)
2
=
64
+
36
=
100
=
(
10
)
2
∴
A
B
=
10
c
m
∴
Each side of rhombus = 10 cm
Answer:
Answer:
We know in rhombus diagonals bisect each other at right angle.
In ΔAOB
AO = 12/2 = 6cm, BO = 16/2 = 8cm
Using Pythagoras theorem in ΔAOB
AB2 = AO2 + BO2
AB2 = 62+ 82
AB2 = 36 + 64
AB2 = 100
AB =√100 = 10cm
∴Each side of a rhombus is 10cm.