If the equation of the circle whose radius is 5 and which touches the circle x^2+y^2−2x−4y−20 = 0 at the point (5, 5) is (x−h)^2+(y−k)^2 = 25, then the value of h^2+k^2 must be
Share
If the equation of the circle whose radius is 5 and which touches the circle x^2+y^2−2x−4y−20 = 0 at the point (5, 5) is (x−h)^2+(y−k)^2 = 25, then the value of h^2+k^2 must be
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
-2x+24ad+h3√4+(23a-2z÷43d)