if the first number is 20% more than the second number then, find how much percent less is the second number from the first one.
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if the first number is 20% more than the second number then, find how much percent less is the second number from the first one.
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Answer:
120%
Step-by-step explanation:
Let the numbers be x and y
2nd number =20 + x
20 + x/x × 100
Let 2nd number be 100
1st number is 100 + 20 = 120
120/100 × 100 = 120%
Answer: Given that,
The second number is 25% more than 100.
The first number is 20% less than the second number.
Now,
The second number is
= 100 + 25% of 100
= 100 + 25
= 125
Similarly,
The second number is
= 125 - 20% of 125
= 125 - 25
= 100
Hence, the first number is 100.
Step-by-step explanation: