if the first number is 20% more than the second number then, find how much percent less is the second number from the first one.
Share
if the first number is 20% more than the second number then, find how much percent less is the second number from the first one.
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Let the numbers be X and Y
2nd number =20+X
20+X/X ×100
Let 2nd number be 100
1st number is 100+20=120
120/100 ×100 =120%