if the length of the diagonal of a Rhombus of 16 cm and 12 cm find its area
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Answer:
A=96cm²
p Diagonal
16
cm
q Diagonal
12
cm
p Diagonal
16
cm
q Diagonal
12
cm
Step-by-step explanation:
A=pq/2
=16·12
=96cm square
Answer:
Area of RHOMBUS is 1/2(Diagnol 1*Diagnol 2)
AREA= 16*12/2
=192/2
= 96