if the polynomials 2 x cube + a x square plus 3 x minus 5 and x cube + 2 x square minus 5 minus A leave the same remainder when divided by x minus 1 then find the value of a
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if the polynomials 2 x cube + a x square plus 3 x minus 5 and x cube + 2 x square minus 5 minus A leave the same remainder when divided by x minus 1 then find the value of a
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Answer:
a=-1
P(x)-2x3tax^2+3x-5
p(x) is divided by x-1
Remainder 2(13+ a(1)^2+3x1-5
=2ta+3-5
a
Again, q(x) = x^3 + 2x^2 - 5x - a
Since, qx) is divided by x-1 then
Remainder = (13+ 2(1^2 5x 1- a
= 1+2-5-a
-2-a
A/Q
Since, Both remainder are equal
Therefore, a = -2-a
2a=-2
a = -1.
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