If the potential difference is 240 V and the electric current is 10 A ,then power of the electric appliance is
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If the potential difference is 240 V and the electric current is 10 A ,then power of the electric appliance is
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Answer:
Here, Power of the electric appliance is 2.4Kw
Explanation:
Here, As given in our question,
=Potential difference(V) across the electric appliance=240v
=Electric current(I) dissipated in the electric appliance=10A
So, Power(P) =V×I
=P=240×10
=P=2400watts or 2.4Kw
So, Power of the electric appliance is 2.4Kw.
Thank you.